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What's given
The bear falls from a height of 10meters. The bear falls in square root of 2 seconds.
The acceleration due to gravity is
g=9.8ms2g equals 9.8 the fraction with numerator m and denominator s squared end-fractionat the equator.
The acceleration due to gravity is g=10ms2g equals 10 the fraction with numerator m and denominator s squared end-fraction at the poles.
The formula for the distance an object falls under gravity is
d=12gt2d equals one-half g t squared.



Calculate the acceleration due to gravity using the given information and compare it to the known values of gravity at the equator and poles.



  1. Step 1 . Calculate the acceleration due to gravity.
    • Use the formula
      1749021132115.gif
      d=12gt2d equals one-half g t squared
      .
    • Rearrange the formula to solve for

      gg
      :
      1749021132184.gif
      g=2dt2g equals the fraction with numerator 2 d and denominator t squared end-fraction
      .
    • Substitute the given values:
      1749021132211.gif
      g=2⋅10(2)2g equals the fraction with numerator 2 center dot 10 and denominator open paren the square root of 2 end-root close paren squared end-fraction
      .
    • Calculate:
      1749021132255.gif
      g=202=10ms2g equals 20 over 2 end-fraction equals 10 the fraction with numerator m and denominator s squared end-fraction
      .

    • Finally white
 

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